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123101430143114 = 261550715071557
BaseRepresentation
bin11011111111010111001001…
…000000111101100010001010
3121010212101022022202110011202
4123333113021000331202022
5112113343212104034424
61113452003304224202
734633533124345223
oct3377271100754212
9533771268673152
10123101430143114
1136251029082745
1211981a6ba6b062
13538c551b3cc27
1422581d8d0424a
15e3723d9302ae
hex6ff5c903d88a

123101430143114 has 4 divisors (see below), whose sum is σ = 184652145214674. Its totient is φ = 61550715071556.

The previous prime is 123101430143099. The next prime is 123101430143137. The reversal of 123101430143114 is 411341034101321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 107750275160089 + 15351154983025 = 10380283^2 + 3918055^2 .

It is a super-2 number, since 2×1231014301431142 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30775357535777 + ... + 30775357535780.

Almost surely, 2123101430143114 is an apocalyptic number.

123101430143114 is a deficient number, since it is larger than the sum of its proper divisors (61550715071560).

123101430143114 is an equidigital number, since it uses as much as digits as its factorization.

123101430143114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61550715071559.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 123101430143114 its reverse (411341034101321), we get a palindrome (534442464244435).

The spelling of 123101430143114 in words is "one hundred twenty-three trillion, one hundred one billion, four hundred thirty million, one hundred forty-three thousand, one hundred fourteen".

Divisors: 1 2 61550715071557 123101430143114