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1231053105151 = 1816801398371
BaseRepresentation
bin10001111010100000011…
…110111010011111111111
311100200120012121022001001
4101322200132322133333
5130132144043331101
62341312112231131
7154640433512212
oct21724036723777
94320505538031
101231053105151
114350a5425661
1217a70523b4a7
138c11abc183c
1443824785779
1522050ed5901
hex11ea07ba7ff

1231053105151 has 4 divisors (see below), whose sum is σ = 1237854503704. Its totient is φ = 1224251706600.

The previous prime is 1231053105133. The next prime is 1231053105157. The reversal of 1231053105151 is 1515013501321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1231053105151 - 221 = 1231051007999 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1231053105157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3400699005 + ... + 3400699366.

It is an arithmetic number, because the mean of its divisors is an integer number (309463625926).

Almost surely, 21231053105151 is an apocalyptic number.

1231053105151 is a deficient number, since it is larger than the sum of its proper divisors (6801398553).

1231053105151 is an equidigital number, since it uses as much as digits as its factorization.

1231053105151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6801398552.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 1231053105151 its reverse (1515013501321), we get a palindrome (2746066606472).

The spelling of 1231053105151 in words is "one trillion, two hundred thirty-one billion, fifty-three million, one hundred five thousand, one hundred fifty-one".

Divisors: 1 181 6801398371 1231053105151