Base | Representation |
---|---|
bin | 1011001100100110110101… |
… | …1111011000011001110111 |
3 | 1121120221101121122101102222 |
4 | 2303021231133120121313 |
5 | 3103201331040311203 |
6 | 42103405425152555 |
7 | 2410312224460004 |
oct | 263115537303167 |
9 | 47527347571388 |
10 | 12311213213303 |
11 | 3a171799a7234 |
12 | 1469bb448b75b |
13 | 6b3c33678444 |
14 | 307c1a0528ab |
15 | 165399c38038 |
hex | b326d7d8677 |
12311213213303 has 4 divisors (see below), whose sum is σ = 12311223133440. Its totient is φ = 12311203293168.
The previous prime is 12311213213293. The next prime is 12311213213311. The reversal of 12311213213303 is 30331231211321.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12311213213303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12311213213003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2778758 + ... + 5687171.
It is an arithmetic number, because the mean of its divisors is an integer number (3077805783360).
Almost surely, 212311213213303 is an apocalyptic number.
12311213213303 is a deficient number, since it is larger than the sum of its proper divisors (9920137).
12311213213303 is an equidigital number, since it uses as much as digits as its factorization.
12311213213303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9920136.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 12311213213303 its reverse (30331231211321), we get a palindrome (42642444424624).
The spelling of 12311213213303 in words is "twelve trillion, three hundred eleven billion, two hundred thirteen million, two hundred thirteen thousand, three hundred three".
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