Base | Representation |
---|---|
bin | 1011001100101010101000… |
… | …1011001001101010101010 |
3 | 1121121001000120101120121002 |
4 | 2303022222023021222222 |
5 | 3103210422204221414 |
6 | 42104054434515002 |
7 | 2410346366313536 |
oct | 263125213115252 |
9 | 47531016346532 |
10 | 12312231320234 |
11 | 3a1765166801a |
12 | 146a239435a62 |
13 | 6b4066585191 |
14 | 307cb5354bc6 |
15 | 1654092e44de |
hex | b32aa2c9aaa |
12312231320234 has 4 divisors (see below), whose sum is σ = 18468346980354. Its totient is φ = 6156115660116.
The previous prime is 12312231320209. The next prime is 12312231320321. The reversal of 12312231320234 is 43202313221321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11101124467225 + 1211106853009 = 3331835^2 + 1100503^2 .
It is a super-3 number, since 3×123122313202343 (a number of 40 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12312231320197 and 12312231320206.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3078057830057 + ... + 3078057830060.
Almost surely, 212312231320234 is an apocalyptic number.
12312231320234 is a deficient number, since it is larger than the sum of its proper divisors (6156115660120).
12312231320234 is an equidigital number, since it uses as much as digits as its factorization.
12312231320234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6156115660119.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 12312231320234 its reverse (43202313221321), we get a palindrome (55514544541555).
The spelling of 12312231320234 in words is "twelve trillion, three hundred twelve billion, two hundred thirty-one million, three hundred twenty thousand, two hundred thirty-four".
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