Base | Representation |
---|---|
bin | 10110111011110101… |
… | …10000101100011101 |
3 | 1011210010021110002210 |
4 | 23131322300230131 |
5 | 200204123300013 |
6 | 5353452311033 |
7 | 614062435602 |
oct | 133572605435 |
9 | 34703243083 |
10 | 12313103133 |
11 | 52494756a1 |
12 | 2477772479 |
13 | 1212c9c756 |
14 | 84b4426a9 |
15 | 4c0ebbcc3 |
hex | 2ddeb0b1d |
12313103133 has 4 divisors (see below), whose sum is σ = 16417470848. Its totient is φ = 8208735420.
The previous prime is 12313103059. The next prime is 12313103137. The reversal of 12313103133 is 33130131321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12313103133 - 29 = 12313102621 is a prime.
It is a super-2 number, since 2×123131031332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12313103137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2052183853 + ... + 2052183858.
It is an arithmetic number, because the mean of its divisors is an integer number (4104367712).
Almost surely, 212313103133 is an apocalyptic number.
It is an amenable number.
12313103133 is a deficient number, since it is larger than the sum of its proper divisors (4104367715).
12313103133 is an equidigital number, since it uses as much as digits as its factorization.
12313103133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4104367714.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 12313103133 its reverse (33130131321), we get a palindrome (45443234454).
The spelling of 12313103133 in words is "twelve billion, three hundred thirteen million, one hundred three thousand, one hundred thirty-three".
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