Base | Representation |
---|---|
bin | 1011001100101110101000… |
… | …0100110111011001000101 |
3 | 1121121010210021201121020020 |
4 | 2303023222010313121011 |
5 | 3103220121133224331 |
6 | 42104353053325353 |
7 | 2410415065052406 |
oct | 263135204673105 |
9 | 47533707647206 |
10 | 12313303414341 |
11 | 3a18051852206 |
12 | 146a498496859 |
13 | 6b41a77150a7 |
14 | 307d778ab9ad |
15 | 16546d4b6c96 |
hex | b32ea137645 |
12313303414341 has 16 divisors (see below), whose sum is σ = 16421029138368. Its totient is φ = 8207223523200.
The previous prime is 12313303414337. The next prime is 12313303414393. The reversal of 12313303414341 is 14341430331321.
12313303414341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12313303414341 - 22 = 12313303414337 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12313303414331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 468226705 + ... + 468253001.
It is an arithmetic number, because the mean of its divisors is an integer number (1026314321148).
Almost surely, 212313303414341 is an apocalyptic number.
It is an amenable number.
12313303414341 is a deficient number, since it is larger than the sum of its proper divisors (4107725724027).
12313303414341 is a wasteful number, since it uses less digits than its factorization.
12313303414341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51652.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 12313303414341 its reverse (14341430331321), we get a palindrome (26654733745662).
The spelling of 12313303414341 in words is "twelve trillion, three hundred thirteen billion, three hundred three million, four hundred fourteen thousand, three hundred forty-one".
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