Base | Representation |
---|---|
bin | 10001111010110001110… |
… | …100101011001000011101 |
3 | 11100201022111000101222211 |
4 | 101322301310223020131 |
5 | 130133243032201140 |
6 | 2341401023440421 |
7 | 154650565331344 |
oct | 21726164531035 |
9 | 4321274011884 |
10 | 1231344022045 |
11 | 435234665845 |
12 | 17a786756111 |
13 | 8c16625c207 |
14 | 43851272b5b |
15 | 2206b7ed2ea |
hex | 11eb1d2b21d |
1231344022045 has 4 divisors (see below), whose sum is σ = 1477612826460. Its totient is φ = 985075217632.
The previous prime is 1231344022021. The next prime is 1231344022061. The reversal of 1231344022045 is 5402204431321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 550080322276 + 681263699769 = 741674^2 + 825387^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1231344022045 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1231344021998 and 1231344022016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123134402200 + ... + 123134402209.
It is an arithmetic number, because the mean of its divisors is an integer number (369403206615).
Almost surely, 21231344022045 is an apocalyptic number.
It is an amenable number.
1231344022045 is a deficient number, since it is larger than the sum of its proper divisors (246268804415).
1231344022045 is an equidigital number, since it uses as much as digits as its factorization.
1231344022045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246268804414.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 1231344022045 its reverse (5402204431321), we get a palindrome (6633548453366).
The spelling of 1231344022045 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, twenty-two thousand, forty-five".
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