Base | Representation |
---|---|
bin | 10001111010110111001… |
… | …101100011101001001111 |
3 | 11100201112210010122211200 |
4 | 101322313031203221033 |
5 | 130133434203243210 |
6 | 2341414013320543 |
7 | 154653043646433 |
oct | 21726715435117 |
9 | 4321483118750 |
10 | 1231434431055 |
11 | 4352806a6434 |
12 | 17a7b0a96153 |
13 | 8c17bbc537a |
14 | 4385d2889c3 |
15 | 2207470b0c0 |
hex | 11eb7363a4f |
1231434431055 has 12 divisors (see below), whose sum is σ = 2134486347240. Its totient is φ = 656765029872.
The previous prime is 1231434431033. The next prime is 1231434431089. The reversal of 1231434431055 is 5501344341321.
1231434431055 is a `hidden beast` number, since 1 + 23 + 143 + 443 + 1 + 0 + 55 = 666.
It is not a de Polignac number, because 1231434431055 - 29 = 1231434430543 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13682604745 + ... + 13682604834.
It is an arithmetic number, because the mean of its divisors is an integer number (177873862270).
Almost surely, 21231434431055 is an apocalyptic number.
1231434431055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1231434431055 is a deficient number, since it is larger than the sum of its proper divisors (903051916185).
1231434431055 is a wasteful number, since it uses less digits than its factorization.
1231434431055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27365209590 (or 27365209587 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 1231434431055 its reverse (5501344341321), we get a palindrome (6732778772376).
The spelling of 1231434431055 in words is "one trillion, two hundred thirty-one billion, four hundred thirty-four million, four hundred thirty-one thousand, fifty-five".
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