1231442110433 has 4 divisors (see below), whose sum is σ = 1244137390020. Its totient is φ = 1218746830848.

The previous prime is 1231442110427. The next prime is 1231442110487. The reversal of 1231442110433 is 3340112441321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 372378211984 + 859063898449 = 610228^2 + 926857^2 .

It is a cyclic number.

It is not a de Polignac number, because 1231442110433 - 2⁸ = 1231442110177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1231442110396 and 1231442110405.

It is not an unprimeable number, because it can be changed into a prime (1231442310433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6347639648 + ... + 6347639841.

It is an arithmetic number, because the mean of its divisors is an integer number (311034347505).

Almost surely, 2^{1231442110433} is an apocalyptic number.

It is an amenable number.

1231442110433 is a deficient number, since it is larger than the sum of its proper divisors (12695279587).

1231442110433 is an equidigital number, since it uses as much as digits as its factorization.

1231442110433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12695279586.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1231442110433 its reverse (3340112441321), we get a palindrome (4571554551754).

The spelling of 1231442110433 in words is "one trillion, two hundred thirty-one billion, four hundred forty-two million, one hundred ten thousand, four hundred thirty-three".