Base | Representation |
---|---|
bin | 1011001100110110011100… |
… | …0111000010010101001001 |
3 | 1121121100012110221212121000 |
4 | 2303031213013002111021 |
5 | 3103233420142313213 |
6 | 42105341151005213 |
7 | 2410521056305344 |
oct | 263154707022511 |
9 | 47540173855530 |
10 | 12315401135433 |
11 | 3a18a28974100 |
12 | 146a982b09809 |
13 | 6b44501b5886 |
14 | 3080d632345b |
15 | 16554272dc73 |
hex | b33671c2549 |
12315401135433 has 96 divisors (see below), whose sum is σ = 20121013059840. Its totient is φ = 7439138150400.
The previous prime is 12315401135399. The next prime is 12315401135441. The reversal of 12315401135433 is 33453110451321.
12315401135433 is a `hidden beast` number, since 1 + 2 + 31 + 540 + 1 + 1 + 3 + 54 + 33 = 666.
It is not a de Polignac number, because 12315401135433 - 29 = 12315401134921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12315401130433) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3354779188 + ... + 3354782858.
It is an arithmetic number, because the mean of its divisors is an integer number (209593886040).
Almost surely, 212315401135433 is an apocalyptic number.
It is an amenable number.
12315401135433 is a deficient number, since it is larger than the sum of its proper divisors (7805611924407).
12315401135433 is a wasteful number, since it uses less digits than its factorization.
12315401135433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6828 (or 6811 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 12315401135433 its reverse (33453110451321), we get a palindrome (45768511586754).
The spelling of 12315401135433 in words is "twelve trillion, three hundred fifteen billion, four hundred one million, one hundred thirty-five thousand, four hundred thirty-three".
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