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123201103130002 = 261600551565001
BaseRepresentation
bin11100000000110011111101…
…111111001110110110010010
3121011012220120201001210202201
4130000303331333032312102
5112122011324400130002
61114005445550233414
734643662120635562
oct3400637577166622
9534186521053681
10123201103130002
113628a326963a77
12119992481b586a
135398a77984291
14225cd7275cda2
15e39b240c2087
hex700cfdfced92

123201103130002 has 4 divisors (see below), whose sum is σ = 184801654695006. Its totient is φ = 61600551565000.

The previous prime is 123201103129999. The next prime is 123201103130041. The reversal of 123201103130002 is 200031301102321.

123201103130002 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112091154210721 + 11109948919281 = 10587311^2 + 3333159^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30800275782499 + ... + 30800275782502.

Almost surely, 2123201103130002 is an apocalyptic number.

123201103130002 is a deficient number, since it is larger than the sum of its proper divisors (61600551565004).

123201103130002 is an equidigital number, since it uses as much as digits as its factorization.

123201103130002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61600551565003.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 123201103130002 its reverse (200031301102321), we get a palindrome (323232404232323).

The spelling of 123201103130002 in words is "one hundred twenty-three trillion, two hundred one billion, one hundred three million, one hundred thirty thousand, two".

Divisors: 1 2 61600551565001 123201103130002