Base | Representation |
---|---|
bin | 10001111011011111000… |
… | …000101011011001000011 |
3 | 11100210021022112222012021 |
4 | 101323133000223121003 |
5 | 130141321122043210 |
6 | 2342004144542311 |
7 | 155005432264213 |
oct | 21733700533103 |
9 | 4323238488167 |
10 | 1232102143555 |
11 | 4355935a2748 |
12 | 17a958621997 |
13 | 8c25733b51a |
14 | 438c3c1a243 |
15 | 220b3151bda |
hex | 11edf02b643 |
1232102143555 has 8 divisors (see below), whose sum is σ = 1481427334800. Its totient is φ = 983745206496.
The previous prime is 1232102143553. The next prime is 1232102143603. The reversal of 1232102143555 is 5553412012321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1232102143555 - 21 = 1232102143553 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1232102143555.
It is not an unprimeable number, because it can be changed into a prime (1232102143553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 242060745 + ... + 242065834.
It is an arithmetic number, because the mean of its divisors is an integer number (185178416850).
Almost surely, 21232102143555 is an apocalyptic number.
1232102143555 is a deficient number, since it is larger than the sum of its proper divisors (249325191245).
1232102143555 is an equidigital number, since it uses as much as digits as its factorization.
1232102143555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 484127093.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 1232102143555 its reverse (5553412012321), we get a palindrome (6785514155876).
The spelling of 1232102143555 in words is "one trillion, two hundred thirty-two billion, one hundred two million, one hundred forty-three thousand, five hundred fifty-five".
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