Base | Representation |
---|---|
bin | 1011001101001100000110… |
… | …0011001110110000111101 |
3 | 1121121220012112211200211120 |
4 | 2303103001203032300331 |
5 | 3103332321120140013 |
6 | 42112142020541153 |
7 | 2411115104150010 |
oct | 263230143166075 |
9 | 47556175750746 |
10 | 12321213443133 |
11 | 3a20440858991 |
12 | 146bb255517b9 |
13 | 6b4b684163ba |
14 | 3084c8235377 |
15 | 165782b3e123 |
hex | b34c18cec3d |
12321213443133 has 8 divisors (see below), whose sum is σ = 18775182389568. Its totient is φ = 7040693396064.
The previous prime is 12321213443131. The next prime is 12321213443141. The reversal of 12321213443133 is 33134431212321.
12321213443133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12321213443133 - 21 = 12321213443131 is a prime.
It is a super-2 number, since 2×123212134431332 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12321213443094 and 12321213443103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12321213443131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 293362224816 + ... + 293362224857.
It is an arithmetic number, because the mean of its divisors is an integer number (2346897798696).
Almost surely, 212321213443133 is an apocalyptic number.
It is an amenable number.
12321213443133 is a deficient number, since it is larger than the sum of its proper divisors (6453968946435).
12321213443133 is an equidigital number, since it uses as much as digits as its factorization.
12321213443133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 586724449683.
The product of its digits is 31104, while the sum is 33.
Adding to 12321213443133 its reverse (33134431212321), we get a palindrome (45455644655454).
The spelling of 12321213443133 in words is "twelve trillion, three hundred twenty-one billion, two hundred thirteen million, four hundred forty-three thousand, one hundred thirty-three".
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