Base | Representation |
---|---|
bin | 11100000000111111111110… |
… | …111101010011000010111011 |
3 | 121011021010212210220020201020 |
4 | 130000333332331103002323 |
5 | 112122214240100131021 |
6 | 1114015422051153523 |
7 | 34644626614042140 |
oct | 3400777675230273 |
9 | 534233783806636 |
10 | 123214004302011 |
11 | 362948472784a7 |
12 | 1199b8488a58a3 |
13 | 539a052732a7c |
14 | 225d837d203c7 |
15 | e3a12ba017c6 |
hex | 700ffef530bb |
123214004302011 has 16 divisors (see below), whose sum is σ = 187828505263104. Its totient is φ = 70380315442944.
The previous prime is 123214004301991. The next prime is 123214004302013. The reversal of 123214004302011 is 110203400412321.
It is not a de Polignac number, because 123214004302011 - 213 = 123214004293819 is a prime.
It is a super-2 number, since 2×1232140043020112 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (123214004302013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1153570966 + ... + 1153677771.
It is an arithmetic number, because the mean of its divisors is an integer number (11739281578944).
Almost surely, 2123214004302011 is an apocalyptic number.
123214004302011 is a deficient number, since it is larger than the sum of its proper divisors (64614500961093).
123214004302011 is a wasteful number, since it uses less digits than its factorization.
123214004302011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2307251290.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 123214004302011 its reverse (110203400412321), we get a palindrome (233417404714332).
The spelling of 123214004302011 in words is "one hundred twenty-three trillion, two hundred fourteen billion, four million, three hundred two thousand, eleven".
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