Base | Representation |
---|---|
bin | 1011001101010011010101… |
… | …0011010000101000011111 |
3 | 1121122002012220000000102021 |
4 | 2303110311103100220133 |
5 | 3103400310241213120 |
6 | 42113102432041011 |
7 | 2411214164502211 |
oct | 263246523205037 |
9 | 47562186000367 |
10 | 12323155413535 |
11 | 3a21247a6aaaa |
12 | 1470387993167 |
13 | 6b50b7853605 |
14 | 3086301065b1 |
15 | 16584838caaa |
hex | b35354d0a1f |
12323155413535 has 16 divisors (see below), whose sum is σ = 14889171016800. Its totient is φ = 9790995367296.
The previous prime is 12323155413509. The next prime is 12323155413557. The reversal of 12323155413535 is 53531455132321.
12323155413535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12323155413535 - 211 = 12323155411487 is a prime.
It is a super-2 number, since 2×123231554135352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12323155413491 and 12323155413500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2169525 + ... + 5417854.
It is an arithmetic number, because the mean of its divisors is an integer number (930573188550).
Almost surely, 212323155413535 is an apocalyptic number.
12323155413535 is a deficient number, since it is larger than the sum of its proper divisors (2566015603265).
12323155413535 is a wasteful number, since it uses less digits than its factorization.
12323155413535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7589610.
The product of its digits is 810000, while the sum is 43.
The spelling of 12323155413535 in words is "twelve trillion, three hundred twenty-three billion, one hundred fifty-five million, four hundred thirteen thousand, five hundred thirty-five".
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