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12324201235 = 52464840247
BaseRepresentation
bin10110111101001010…
…00110001100010011
31011210220011021211121
423132211012030103
5200214443414420
65354530223111
7614255660563
oct133645061423
934726137747
1012324201235
115254765885
12247b424a97
131215387088
1484cad0da3
154c1e602aa
hex2de946313

12324201235 has 4 divisors (see below), whose sum is σ = 14789041488. Its totient is φ = 9859360984.

The previous prime is 12324201199. The next prime is 12324201271. The reversal of 12324201235 is 53210242321.

12324201235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12324201199) and next prime (12324201271).

It is a cyclic number.

It is not a de Polignac number, because 12324201235 - 221 = 12322104083 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1232420119 + ... + 1232420128.

It is an arithmetic number, because the mean of its divisors is an integer number (3697260372).

Almost surely, 212324201235 is an apocalyptic number.

12324201235 is a deficient number, since it is larger than the sum of its proper divisors (2464840253).

12324201235 is an equidigital number, since it uses as much as digits as its factorization.

12324201235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2464840252.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 12324201235 its reverse (53210242321), we get a palindrome (65534443556).

The spelling of 12324201235 in words is "twelve billion, three hundred twenty-four million, two hundred one thousand, two hundred thirty-five".

Divisors: 1 5 2464840247 12324201235