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12325433 = 192232909
BaseRepresentation
bin101111000001…
…001000111001
3212012012022112
4233001020321
511123403213
61120102105
7206523131
oct57011071
925165275
1012325433
116a5930a
124164935
132727173
1418cbac1
151136ea8
hexbc1239

12325433 has 8 divisors (see below), whose sum is σ = 13036800. Its totient is φ = 11620368.

The previous prime is 12325427. The next prime is 12325441. The reversal of 12325433 is 33452321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12325433 - 210 = 12324409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12325399 and 12325408.

It is not an unprimeable number, because it can be changed into a prime (12345433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2783 + ... + 5691.

It is an arithmetic number, because the mean of its divisors is an integer number (1629600).

Almost surely, 212325433 is an apocalyptic number.

It is an amenable number.

12325433 is a deficient number, since it is larger than the sum of its proper divisors (711367).

12325433 is a wasteful number, since it uses less digits than its factorization.

12325433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3151.

The product of its digits is 2160, while the sum is 23.

The square root of 12325433 is about 3510.7596044161. The cubic root of 12325433 is about 230.9940154494.

Adding to 12325433 its reverse (33452321), we get a palindrome (45777754).

The spelling of 12325433 in words is "twelve million, three hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 19 223 2909 4237 55271 648707 12325433