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12345433 is a prime number
BaseRepresentation
bin101111000110…
…000001011001
3212020012202021
4233012001121
511130023213
61120334441
7206635342
oct57060131
925205667
1012345433
116a72341
124174421
1327332b9
1418d50c9
15113cd8d
hexbc6059

12345433 has 2 divisors, whose sum is σ = 12345434. Its totient is φ = 12345432.

The previous prime is 12345427. The next prime is 12345439. The reversal of 12345433 is 33454321.

It is a balanced prime because it is at equal distance from previous prime (12345427) and next prime (12345439).

It can be written as a sum of positive squares in only one way, i.e., 11108889 + 1236544 = 3333^2 + 1112^2 .

It is a cyclic number.

It is not a de Polignac number, because 12345433 - 29 = 12344921 is a prime.

It is equal to p809206 and since 12345433 and 809206 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 12345398 and 12345407.

It is not a weakly prime, because it can be changed into another prime (12345439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6172716 + 6172717.

It is an arithmetic number, because the mean of its divisors is an integer number (6172717).

Almost surely, 212345433 is an apocalyptic number.

It is an amenable number.

12345433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12345433 is an equidigital number, since it uses as much as digits as its factorization.

12345433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 25.

The square root of 12345433 is about 3513.6068362866. The cubic root of 12345433 is about 231.1188895944.

Adding to 12345433 its reverse (33454321), we get a palindrome (45799754).

The spelling of 12345433 in words is "twelve million, three hundred forty-five thousand, four hundred thirty-three".