123301402523101 has 4 divisors (see below), whose sum is σ = 134510620934304. Its totient is φ = 112092184111900.

The previous prime is 123301402523087. The next prime is 123301402523119. The reversal of 123301402523101 is 101325204103321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 123301402523101 - 2⁹ = 123301402522589 is a prime.

It is a super-3 number, since 3×123301402523101³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123301402523101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123301402524101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5604609205585 + ... + 5604609205606.

It is an arithmetic number, because the mean of its divisors is an integer number (33627655233576).

Almost surely, 2^{123301402523101} is an apocalyptic number.

123301402523101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

123301402523101 is a deficient number, since it is larger than the sum of its proper divisors (11209218411203).

123301402523101 is a wasteful number, since it uses less digits than its factorization.

123301402523101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11209218411202.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 123301402523101 its reverse (101325204103321), we get a palindrome (224626606626422).

The spelling of 123301402523101 in words is "one hundred twenty-three trillion, three hundred one billion, four hundred two million, five hundred twenty-three thousand, one hundred one".