Base | Representation |
---|---|
bin | 1011001101110000100011… |
… | …1000011001110000101010 |
3 | 1121122211110121011220002022 |
4 | 2303130020320121300222 |
5 | 3104012342012010442 |
6 | 42120441103104442 |
7 | 2411612451353561 |
oct | 263341070316052 |
9 | 47584417156068 |
10 | 12331000110122 |
11 | 3a24603103721 |
12 | 14719b6ba2122 |
13 | 6b5a67b5b905 |
14 | 308b75d04bd8 |
15 | 165b56e0c3d2 |
hex | b3708e19c2a |
12331000110122 has 4 divisors (see below), whose sum is σ = 18496500165186. Its totient is φ = 6165500055060.
The previous prime is 12331000110061. The next prime is 12331000110199. The reversal of 12331000110122 is 22101100013321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6612823114681 + 5718176995441 = 2571541^2 + 2391271^2 .
It is a super-2 number, since 2×123310001101222 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12331000110122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3082750027529 + ... + 3082750027532.
Almost surely, 212331000110122 is an apocalyptic number.
12331000110122 is a deficient number, since it is larger than the sum of its proper divisors (6165500055064).
12331000110122 is an equidigital number, since it uses as much as digits as its factorization.
12331000110122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6165500055063.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12331000110122 its reverse (22101100013321), we get a palindrome (34432100123443).
The spelling of 12331000110122 in words is "twelve trillion, three hundred thirty-one billion, one hundred ten thousand, one hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •