12331002113 has 4 divisors (see below), whose sum is σ = 12617769648. Its totient is φ = 12044234580.

The previous prime is 12331002083. The next prime is 12331002157. The reversal of 12331002113 is 31120013321.

12331002113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31120013321 = 47 ⋅662127943.

It is a cyclic number.

It is not a de Polignac number, because 12331002113 - 2⁶ = 12331002049 is a prime.

It is a super-2 number, since 2×12331002113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12331002091 and 12331002100.

It is not an unprimeable number, because it can be changed into a prime (12331002713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143383703 + ... + 143383788.

It is an arithmetic number, because the mean of its divisors is an integer number (3154442412).

Almost surely, 2^12331002113 is an apocalyptic number.

It is an amenable number.

12331002113 is a deficient number, since it is larger than the sum of its proper divisors (286767535).

12331002113 is an equidigital number, since it uses as much as digits as its factorization.

12331002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 286767534.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12331002113 its reverse (31120013321), we get a palindrome (43451015434).

The spelling of 12331002113 in words is "twelve billion, three hundred thirty-one million, two thousand, one hundred thirteen".