Base | Representation |
---|---|
bin | 10110111101111110… |
… | …11101001011011101 |
3 | 1011211101011100102202 |
4 | 23132333131023131 |
5 | 200223231024013 |
6 | 5355334301245 |
7 | 614401500215 |
oct | 133677351335 |
9 | 34741140382 |
10 | 12331111133 |
11 | 5258655340 |
12 | 24817b7825 |
13 | 1216936283 |
14 | 84d9ad245 |
15 | 4c2877858 |
hex | 2defdd2dd |
12331111133 has 4 divisors (see below), whose sum is σ = 13452121248. Its totient is φ = 11210101020.
The previous prime is 12331111063. The next prime is 12331111147. The reversal of 12331111133 is 33111113321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12331111133 - 214 = 12331094749 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12331111153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560505041 + ... + 560505062.
It is an arithmetic number, because the mean of its divisors is an integer number (3363030312).
Almost surely, 212331111133 is an apocalyptic number.
It is an amenable number.
12331111133 is a deficient number, since it is larger than the sum of its proper divisors (1121010115).
12331111133 is a wasteful number, since it uses less digits than its factorization.
12331111133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1121010114.
The product of its digits is 162, while the sum is 20.
Adding to 12331111133 its reverse (33111113321), we get a palindrome (45442224454).
The spelling of 12331111133 in words is "twelve billion, three hundred thirty-one million, one hundred eleven thousand, one hundred thirty-three".
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