12331214433 has 6 divisors (see below), whose sum is σ = 17811754194. Its totient is φ = 8220809616.

The previous prime is 12331214417. The next prime is 12331214449. The reversal of 12331214433 is 33441213321.

It is a happy number.

12331214433 is a `hidden beast` number, since 12 + 3 + 3 + 1 + 214 + 433 = 666.

It is an interprime number because it is at equal distance from previous prime (12331214417) and next prime (12331214449).

It can be written as a sum of positive squares in only one way, i.e., 12313675089 + 17539344 = 110967^2 + 4188^2 .

It is not a de Polignac number, because 12331214433 - 2⁴ = 12331214417 is a prime.

It is a super-2 number, since 2×12331214433² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12331214397 and 12331214406.

It is not an unprimeable number, because it can be changed into a prime (12331294433) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 685067460 + ... + 685067477.

It is an arithmetic number, because the mean of its divisors is an integer number (2968625699).

Almost surely, 2^12331214433 is an apocalyptic number.

It is an amenable number.

12331214433 is a deficient number, since it is larger than the sum of its proper divisors (5480539761).

12331214433 is a wasteful number, since it uses less digits than its factorization.

12331214433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1370134943 (or 1370134940 counting only the distinct ones).

The product of its digits is 5184, while the sum is 27.

Adding to 12331214433 its reverse (33441213321), we get a palindrome (45772427754).

The spelling of 12331214433 in words is "twelve billion, three hundred thirty-one million, two hundred fourteen thousand, four hundred thirty-three".