Base | Representation |
---|---|
bin | 111001011011000010… |
… | …1101100111100011011 |
3 | 102210021222002220022121 |
4 | 1302312011230330123 |
5 | 4010021343014121 |
6 | 132352155402111 |
7 | 11623556660323 |
oct | 1626605547433 |
9 | 383258086277 |
10 | 123314032411 |
11 | 4832a613789 |
12 | 1ba95753337 |
13 | b8229707ab |
14 | 5d7b536283 |
15 | 331adcb141 |
hex | 1cb616cf1b |
123314032411 has 4 divisors (see below), whose sum is σ = 124002937800. Its totient is φ = 122625127024.
The previous prime is 123314032397. The next prime is 123314032417. The reversal of 123314032411 is 114230413321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123314032411 - 235 = 88954294043 is a prime.
It is a super-5 number, since 5×1233140324115 (a number of 57 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123314032417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 344452426 + ... + 344452783.
It is an arithmetic number, because the mean of its divisors is an integer number (31000734450).
Almost surely, 2123314032411 is an apocalyptic number.
123314032411 is a deficient number, since it is larger than the sum of its proper divisors (688905389).
123314032411 is an equidigital number, since it uses as much as digits as its factorization.
123314032411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 688905388.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 123314032411 its reverse (114230413321), we get a palindrome (237544445732).
The spelling of 123314032411 in words is "one hundred twenty-three billion, three hundred fourteen million, thirty-two thousand, four hundred eleven".
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