Base | Representation |
---|---|
bin | 11100000010011110010110… |
… | …001011001001011101111111 |
3 | 121011121211102001200110001112 |
4 | 130002132112023021131333 |
5 | 112130344241314241343 |
6 | 1114134140053032235 |
7 | 34655144503255115 |
oct | 3402362613113577 |
9 | 534554361613045 |
10 | 123315325540223 |
11 | 36323810497403 |
12 | 119b740502567b |
13 | 53a677bba536b |
14 | 22646ca62dab5 |
15 | e3caabc24218 |
hex | 7027962c977f |
123315325540223 has 16 divisors (see below), whose sum is σ = 125547003331680. Its totient is φ = 121095608933376.
The previous prime is 123315325540217. The next prime is 123315325540247. The reversal of 123315325540223 is 322045523513321.
It is a cyclic number.
It is not a de Polignac number, because 123315325540223 - 24 = 123315325540207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123315325540283) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33925211 + ... + 37383827.
It is an arithmetic number, because the mean of its divisors is an integer number (7846687708230).
Almost surely, 2123315325540223 is an apocalyptic number.
123315325540223 is a deficient number, since it is larger than the sum of its proper divisors (2231677791457).
123315325540223 is a wasteful number, since it uses less digits than its factorization.
123315325540223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3460346.
The product of its (nonzero) digits is 648000, while the sum is 41.
The spelling of 123315325540223 in words is "one hundred twenty-three trillion, three hundred fifteen billion, three hundred twenty-five million, five hundred forty thousand, two hundred twenty-three".
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