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12332015313 = 34110671771
BaseRepresentation
bin10110111110000101…
…11001111011010001
31011211102212021201220
423133002321323101
5200223443442223
65355405515253
7614412254262
oct133702717321
934742767656
1012332015313
1152591126a2
122481b72b29
131216b919a7
1484db66969
154c29a56e3
hex2df0b9ed1

12332015313 has 4 divisors (see below), whose sum is σ = 16442687088. Its totient is φ = 8221343540.

The previous prime is 12332015309. The next prime is 12332015323. The reversal of 12332015313 is 31351023321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12332015313 - 22 = 12332015309 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12332015323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2055335883 + ... + 2055335888.

It is an arithmetic number, because the mean of its divisors is an integer number (4110671772).

Almost surely, 212332015313 is an apocalyptic number.

It is an amenable number.

12332015313 is a deficient number, since it is larger than the sum of its proper divisors (4110671775).

12332015313 is an equidigital number, since it uses as much as digits as its factorization.

12332015313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4110671774.

The product of its (nonzero) digits is 1620, while the sum is 24.

Adding to 12332015313 its reverse (31351023321), we get a palindrome (43683038634).

The spelling of 12332015313 in words is "twelve billion, three hundred thirty-two million, fifteen thousand, three hundred thirteen".

Divisors: 1 3 4110671771 12332015313