Search a number
-
+
123320255054351 = 867463142161977
BaseRepresentation
bin11100000010100010111011…
…111111110000001000001111
3121011122022010121102201011212
4130002202323333300020033
5112130434340243214401
61114140313145405035
734655410611403325
oct3402427377601017
9534568117381155
10123320255054351
1136325910031323
12119b835ba9977b
1353a7086255224
142264a371c3d15
15e3cc998a5dbb
hex7028bbff020f

123320255054351 has 4 divisors (see below), whose sum is σ = 123320398083792. Its totient is φ = 123320112024912.

The previous prime is 123320255054329. The next prime is 123320255054393. The reversal of 123320255054351 is 153450552023321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123320255054351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123320255054299 and 123320255054308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123320255074351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70213526 + ... + 71948451.

It is an arithmetic number, because the mean of its divisors is an integer number (30830099520948).

Almost surely, 2123320255054351 is an apocalyptic number.

123320255054351 is a deficient number, since it is larger than the sum of its proper divisors (143029441).

123320255054351 is an equidigital number, since it uses as much as digits as its factorization.

123320255054351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143029440.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 123320255054351 in words is "one hundred twenty-three trillion, three hundred twenty billion, two hundred fifty-five million, fifty-four thousand, three hundred fifty-one".

Divisors: 1 867463 142161977 123320255054351