Base | Representation |
---|---|
bin | 11100000010100011001011… |
… | …110011010101010010101011 |
3 | 121011122022211002102020111002 |
4 | 130002203023303111102223 |
5 | 112130440411134443110 |
6 | 1114140355341225215 |
7 | 34655420311400306 |
oct | 3402431363252253 |
9 | 534568732366432 |
10 | 123320520234155 |
11 | 36325a36792892 |
12 | 119b841486220b |
13 | 53a70c918105a |
14 | 2264a604d1b3d |
15 | e3ccb2cd7aa5 |
hex | 7028cbcd54ab |
123320520234155 has 4 divisors (see below), whose sum is σ = 147984624280992. Its totient is φ = 98656416187320.
The previous prime is 123320520234077. The next prime is 123320520234161. The reversal of 123320520234155 is 551432025023321.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 123320520234155 - 216 = 123320520168619 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12332052023411 + ... + 12332052023420.
It is an arithmetic number, because the mean of its divisors is an integer number (36996156070248).
Almost surely, 2123320520234155 is an apocalyptic number.
123320520234155 is a deficient number, since it is larger than the sum of its proper divisors (24664104046837).
123320520234155 is an equidigital number, since it uses as much as digits as its factorization.
123320520234155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24664104046836.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 123320520234155 its reverse (551432025023321), we get a palindrome (674752545257476).
The spelling of 123320520234155 in words is "one hundred twenty-three trillion, three hundred twenty billion, five hundred twenty million, two hundred thirty-four thousand, one hundred fifty-five".
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