Base | Representation |
---|---|
bin | 10001111100100001001… |
… | …010111111110110001011 |
3 | 11100220010200012212222012 |
4 | 101330201022333312023 |
5 | 130201104302120120 |
6 | 2342310240050135 |
7 | 155045101164143 |
oct | 21744112776613 |
9 | 4326120185865 |
10 | 1233212145035 |
11 | 436003119242 |
12 | 17b00830394b |
13 | 8c3a32b1630 |
14 | 4398b3dd923 |
15 | 2212a8111c5 |
hex | 11f212bfd8b |
1233212145035 has 16 divisors (see below), whose sum is σ = 1593831388800. Its totient is φ = 910598682240.
The previous prime is 1233212144963. The next prime is 1233212145037. The reversal of 1233212145035 is 5305412123321.
It is not a de Polignac number, because 1233212145035 - 220 = 1233211096459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1233212144992 and 1233212145010.
It is not an unprimeable number, because it can be changed into a prime (1233212145037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103460 + ... + 1573889.
It is an arithmetic number, because the mean of its divisors is an integer number (99614461800).
Almost surely, 21233212145035 is an apocalyptic number.
1233212145035 is a deficient number, since it is larger than the sum of its proper divisors (360619243765).
1233212145035 is a wasteful number, since it uses less digits than its factorization.
1233212145035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1688678.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1233212145035 its reverse (5305412123321), we get a palindrome (6538624268356).
The spelling of 1233212145035 in words is "one trillion, two hundred thirty-three billion, two hundred twelve million, one hundred forty-five thousand, thirty-five".
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