Base | Representation |
---|---|
bin | 10001111100100001001… |
… | …100000100001110101011 |
3 | 11100220010200202010012010 |
4 | 101330201030010032223 |
5 | 130201104340101011 |
6 | 2342310250051003 |
7 | 155045103441561 |
oct | 21744114041653 |
9 | 4326120663163 |
10 | 1233212425131 |
11 | 43600329a725 |
12 | 17b008419a63 |
13 | 8c3a337bc7b |
14 | 4398b473a31 |
15 | 2212a8691a6 |
hex | 11f213043ab |
1233212425131 has 8 divisors (see below), whose sum is σ = 1653469174080. Its totient is φ = 817548646472.
The previous prime is 1233212425099. The next prime is 1233212425141. The reversal of 1233212425131 is 1315242123321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1233212425131 - 25 = 1233212425099 is a prime.
It is a super-2 number, since 2×12332124251312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1233212425141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1148241945 + ... + 1148243018.
It is an arithmetic number, because the mean of its divisors is an integer number (206683646760).
Almost surely, 21233212425131 is an apocalyptic number.
1233212425131 is a deficient number, since it is larger than the sum of its proper divisors (420256748949).
1233212425131 is a wasteful number, since it uses less digits than its factorization.
1233212425131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2296485145.
The product of its digits is 8640, while the sum is 30.
Adding to 1233212425131 its reverse (1315242123321), we get a palindrome (2548454548452).
It can be divided in two parts, 123321 and 2425131, that added together give a palindrome (2548452).
The spelling of 1233212425131 in words is "one trillion, two hundred thirty-three billion, two hundred twelve million, four hundred twenty-five thousand, one hundred thirty-one".
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