Base | Representation |
---|---|
bin | 1011001101111000000010… |
… | …1100010101010010011001 |
3 | 1121200000122200112122110202 |
4 | 2303132000230111102121 |
5 | 3104031001103240433 |
6 | 42121412350351545 |
7 | 2412013330061102 |
oct | 263360054252231 |
9 | 47600580478422 |
10 | 12333010211993 |
11 | 3a2544481aa39 |
12 | 14722781bb5b5 |
13 | 6b5cc8431cc3 |
14 | 308cc6c6d3a9 |
15 | 165c23617ee8 |
hex | b3780b15499 |
12333010211993 has 4 divisors (see below), whose sum is σ = 12506714581248. Its totient is φ = 12159305842740.
The previous prime is 12333010211983. The next prime is 12333010212001. The reversal of 12333010211993 is 39911201033321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12333010211993 - 212 = 12333010207897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12333010211983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86852184521 + ... + 86852184662.
It is an arithmetic number, because the mean of its divisors is an integer number (3126678645312).
Almost surely, 212333010211993 is an apocalyptic number.
It is an amenable number.
12333010211993 is a deficient number, since it is larger than the sum of its proper divisors (173704369255).
12333010211993 is an equidigital number, since it uses as much as digits as its factorization.
12333010211993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173704369254.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 12333010211993 in words is "twelve trillion, three hundred thirty-three billion, ten million, two hundred eleven thousand, nine hundred ninety-three".
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