Base | Representation |
---|---|
bin | 1011001101111000110010… |
… | …1110001000111001100100 |
3 | 1121200001011202021011012222 |
4 | 2303132030232020321210 |
5 | 3104031404233342012 |
6 | 42121444355531512 |
7 | 2412021330253514 |
oct | 263361456107144 |
9 | 47601152234188 |
10 | 12333212012132 |
11 | 3a25538722410 |
12 | 14723138b9b98 |
13 | 6b602b19977b |
14 | 308d0599d844 |
15 | 165c361ca972 |
hex | b378cb88e64 |
12333212012132 has 12 divisors (see below), whose sum is σ = 23545222932336. Its totient is φ = 5606005460040.
The previous prime is 12333212012131. The next prime is 12333212012137. The reversal of 12333212012132 is 23121021233321.
12333212012132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×123332120121322 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12333212012131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140150136458 + ... + 140150136545.
It is an arithmetic number, because the mean of its divisors is an integer number (1962101911028).
Almost surely, 212333212012132 is an apocalyptic number.
It is an amenable number.
12333212012132 is a deficient number, since it is larger than the sum of its proper divisors (11212010920204).
12333212012132 is a wasteful number, since it uses less digits than its factorization.
12333212012132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280300273018 (or 280300273016 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 12333212012132 its reverse (23121021233321), we get a palindrome (35454233245453).
The spelling of 12333212012132 in words is "twelve trillion, three hundred thirty-three billion, two hundred twelve million, twelve thousand, one hundred thirty-two".
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