Base | Representation |
---|---|
bin | 1011001110010111010011… |
… | …0001010000010000101010 |
3 | 1121200211022101121122001111 |
4 | 2303211310301100100222 |
5 | 3104200141412010442 |
6 | 42125321055140534 |
7 | 2412431254040356 |
oct | 263456461202052 |
9 | 47624271548044 |
10 | 12341400110122 |
11 | 3a28a5a693646 |
12 | 1473a19b1474a |
13 | 6b6a3468a675 |
14 | 30948122c466 |
15 | 166064e7db17 |
hex | b3974c5042a |
12341400110122 has 4 divisors (see below), whose sum is σ = 18512100165186. Its totient is φ = 6170700055060.
The previous prime is 12341400110111. The next prime is 12341400110177. The reversal of 12341400110122 is 22101100414321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10977155086041 + 1364245024081 = 3313179^2 + 1168009^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12341400110093 and 12341400110102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3085350027529 + ... + 3085350027532.
Almost surely, 212341400110122 is an apocalyptic number.
12341400110122 is a deficient number, since it is larger than the sum of its proper divisors (6170700055064).
12341400110122 is an equidigital number, since it uses as much as digits as its factorization.
12341400110122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6170700055063.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12341400110122 its reverse (22101100414321), we get a palindrome (34442500524443).
The spelling of 12341400110122 in words is "twelve trillion, three hundred forty-one billion, four hundred million, one hundred ten thousand, one hundred twenty-two".
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