Base | Representation |
---|---|
bin | 1011001110011010010010… |
… | …0001101011010111100111 |
3 | 1121200220101020020222112011 |
4 | 2303212210201223113213 |
5 | 3104203312020130343 |
6 | 42125532400135051 |
7 | 2412460153236646 |
oct | 263464441532747 |
9 | 47626336228464 |
10 | 12342201333223 |
11 | 3a2933098a3a3 |
12 | 1474002307487 |
13 | 6b6b3167b188 |
14 | 3095197d535d |
15 | 1660b049829d |
hex | b39a486b5e7 |
12342201333223 has 8 divisors (see below), whose sum is σ = 12411253209600. Its totient is φ = 12273150579768.
The previous prime is 12342201333221. The next prime is 12342201333271. The reversal of 12342201333223 is 32233310224321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12342201333223 - 21 = 12342201333221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12342201333221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32317098 + ... + 32696776.
It is an arithmetic number, because the mean of its divisors is an integer number (1551406651200).
Almost surely, 212342201333223 is an apocalyptic number.
12342201333223 is a deficient number, since it is larger than the sum of its proper divisors (69051876377).
12342201333223 is a wasteful number, since it uses less digits than its factorization.
12342201333223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 561461.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 12342201333223 its reverse (32233310224321), we get a palindrome (44575511557544).
The spelling of 12342201333223 in words is "twelve trillion, three hundred forty-two billion, two hundred one million, three hundred thirty-three thousand, two hundred twenty-three".
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