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12343340041 = 18676611323
BaseRepresentation
bin10110111111011100…
…00110110000001001
31011212020011122100021
423133232012300021
5200234343340131
65400452340441
7614610442054
oct133756066011
934766148307
1012343340041
11526454807a
122485914721
131219328506
14851473a9b
154c3990e11
hex2dfb86c09

12343340041 has 4 divisors (see below), whose sum is σ = 12349953232. Its totient is φ = 12336726852.

The previous prime is 12343340033. The next prime is 12343340083. The reversal of 12343340041 is 14004334321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12343340041 - 23 = 12343340033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12343339988 and 12343340015.

It is not an unprimeable number, because it can be changed into a prime (12343341041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3303795 + ... + 3307528.

It is an arithmetic number, because the mean of its divisors is an integer number (3087488308).

Almost surely, 212343340041 is an apocalyptic number.

It is an amenable number.

12343340041 is a deficient number, since it is larger than the sum of its proper divisors (6613191).

12343340041 is an equidigital number, since it uses as much as digits as its factorization.

12343340041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6613190.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 12343340041 its reverse (14004334321), we get a palindrome (26347674362).

The spelling of 12343340041 in words is "twelve billion, three hundred forty-three million, three hundred forty thousand, forty-one".

Divisors: 1 1867 6611323 12343340041