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12343500115315 = 52468700023063
BaseRepresentation
bin1011001110011111000111…
…1100001000110101110011
31121201000201202010221121121
42303213301330020311303
53104213442012142230
642130305313403111
72412534303555445
oct263476174106563
947630652127547
1012343500115315
113a29938025626
121474305269497
136b6caa77a9a5
143096000ba495
151661394e777a
hexb39f1f08d73

12343500115315 has 4 divisors (see below), whose sum is σ = 14812200138384. Its totient is φ = 9874800092248.

The previous prime is 12343500115313. The next prime is 12343500115339. The reversal of 12343500115315 is 51351100534321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12343500115315 - 21 = 12343500115313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12343500115313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1234350011527 + ... + 1234350011536.

It is an arithmetic number, because the mean of its divisors is an integer number (3703050034596).

Almost surely, 212343500115315 is an apocalyptic number.

12343500115315 is a deficient number, since it is larger than the sum of its proper divisors (2468700023069).

12343500115315 is an equidigital number, since it uses as much as digits as its factorization.

12343500115315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2468700023068.

The product of its (nonzero) digits is 27000, while the sum is 34.

Adding to 12343500115315 its reverse (51351100534321), we get a palindrome (63694600649636).

The spelling of 12343500115315 in words is "twelve trillion, three hundred forty-three billion, five hundred million, one hundred fifteen thousand, three hundred fifteen".

Divisors: 1 5 2468700023063 12343500115315