Search a number
-
+
12344241153 = 34114747051
BaseRepresentation
bin10110111111100011…
…00010110000000001
31011212021212102102210
423133301202300001
5200240111204103
65400523532333
7614621214156
oct133761426001
934767772383
1012344241153
1152650030a2
12248608a0a9
13121958270a
1485162a22d
154c3abce03
hex2dfc62c01

12344241153 has 4 divisors (see below), whose sum is σ = 16458988208. Its totient is φ = 8229494100.

The previous prime is 12344241101. The next prime is 12344241167. The reversal of 12344241153 is 35114244321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12344241153 - 217 = 12344110081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12344241153.

It is not an unprimeable number, because it can be changed into a prime (12344241053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2057373523 + ... + 2057373528.

It is an arithmetic number, because the mean of its divisors is an integer number (4114747052).

Almost surely, 212344241153 is an apocalyptic number.

It is an amenable number.

12344241153 is a deficient number, since it is larger than the sum of its proper divisors (4114747055).

12344241153 is an equidigital number, since it uses as much as digits as its factorization.

12344241153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4114747054.

The product of its digits is 11520, while the sum is 30.

Adding to 12344241153 its reverse (35114244321), we get a palindrome (47458485474).

The spelling of 12344241153 in words is "twelve billion, three hundred forty-four million, two hundred forty-one thousand, one hundred fifty-three".

Divisors: 1 3 4114747051 12344241153