1235014668353 has 4 divisors (see below), whose sum is σ = 1237177566768. Its totient is φ = 1232851769940.

The previous prime is 1235014668347. The next prime is 1235014668383. The reversal of 1235014668353 is 3538664105321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1235014668353 - 2⁶ = 1235014668289 is a prime.

It is a super-2 number, since 2×1235014668353² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1235014668298 and 1235014668307.

It is not an unprimeable number, because it can be changed into a prime (1235014668343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1081448351 + ... + 1081449492.

It is an arithmetic number, because the mean of its divisors is an integer number (309294391692).

Almost surely, 2^{1235014668353} is an apocalyptic number.

It is an amenable number.

1235014668353 is a deficient number, since it is larger than the sum of its proper divisors (2162898415).

1235014668353 is an equidigital number, since it uses as much as digits as its factorization.

1235014668353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2162898414.

The product of its (nonzero) digits is 1555200, while the sum is 47.

The spelling of 1235014668353 in words is "one trillion, two hundred thirty-five billion, fourteen million, six hundred sixty-eight thousand, three hundred fifty-three".