12351604145533 has 4 divisors (see below), whose sum is σ = 12354966960028. Its totient is φ = 12348241331040.

The previous prime is 12351604145497. The next prime is 12351604145537. The reversal of 12351604145533 is 33554140615321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6701460883524 + 5650143262009 = 2588718^2 + 2377003^2 .

It is a cyclic number.

It is not a de Polignac number, because 12351604145533 - 2²¹ = 12351602048381 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12351604145533.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12351604145537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1681401738 + ... + 1681409083.

It is an arithmetic number, because the mean of its divisors is an integer number (3088741740007).

Almost surely, 2^{12351604145533} is an apocalyptic number.

It is an amenable number.

12351604145533 is a deficient number, since it is larger than the sum of its proper divisors (3362814495).

12351604145533 is an equidigital number, since it uses as much as digits as its factorization.

12351604145533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3362814494.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 12351604145533 in words is "twelve trillion, three hundred fifty-one billion, six hundred four million, one hundred forty-five thousand, five hundred thirty-three".