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123530000458 = 261765000229
BaseRepresentation
bin111001100001011110…
…1100011100001001010
3102210212000111012210011
41303002331203201022
54010442140003313
6132425432342134
711632121451634
oct1630275434112
9383760435704
10123530000458
1148430512777
121bb35b4494a
13b858628c37
145d9c0b3a54
15332ed3b93d
hex1cc2f6384a

123530000458 has 4 divisors (see below), whose sum is σ = 185295000690. Its totient is φ = 61765000228.

The previous prime is 123530000417. The next prime is 123530000459. The reversal of 123530000458 is 854000035321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 120309778449 + 3220222009 = 346857^2 + 56747^2 .

It is a super-2 number, since 2×1235300004582 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (123530000459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30882500113 + ... + 30882500116.

Almost surely, 2123530000458 is an apocalyptic number.

123530000458 is a deficient number, since it is larger than the sum of its proper divisors (61765000232).

123530000458 is an equidigital number, since it uses as much as digits as its factorization.

123530000458 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61765000231.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 123530000458 its reverse (854000035321), we get a palindrome (977530035779).

The spelling of 123530000458 in words is "one hundred twenty-three billion, five hundred thirty million, four hundred fifty-eight", and thus it is an aban number.

Divisors: 1 2 61765000229 123530000458