123530151433 has 4 divisors (see below), whose sum is σ = 133032470788. Its totient is φ = 114027832080.

The previous prime is 123530151413. The next prime is 123530151457. The reversal of 123530151433 is 334151035321.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50677663689 + 72852487744 = 225117^2 + 269912^2 .

It is a cyclic number.

It is not a de Polignac number, because 123530151433 - 2¹³ = 123530143241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123530151395 and 123530151404.

It is not an unprimeable number, because it can be changed into a prime (123530151413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4751159658 + ... + 4751159683.

It is an arithmetic number, because the mean of its divisors is an integer number (33258117697).

Almost surely, 2^123530151433 is an apocalyptic number.

123530151433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

123530151433 is a deficient number, since it is larger than the sum of its proper divisors (9502319355).

123530151433 is an equidigital number, since it uses as much as digits as its factorization.

123530151433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9502319354.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 123530151433 its reverse (334151035321), we get a palindrome (457681186754).

The spelling of 123530151433 in words is "one hundred twenty-three billion, five hundred thirty million, one hundred fifty-one thousand, four hundred thirty-three".