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12353250416601 = 34117750138867
BaseRepresentation
bin1011001111000011011100…
…0110100101011111011001
31121201221220021001120111110
42303300313012211133121
53104343424101312401
642135001020250533
72413331030012013
oct263606706453731
947657807046443
1012353250416601
113a32a908a2266
1214761866a0a49
136b7ba27cc933
14309c870011b3
1516650a4d09d6
hexb3c371a57d9

12353250416601 has 4 divisors (see below), whose sum is σ = 16471000555472. Its totient is φ = 8235500277732.

The previous prime is 12353250416599. The next prime is 12353250416629. The reversal of 12353250416601 is 10661405235321.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12353250416601 - 21 = 12353250416599 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12353250416601.

It is not an unprimeable number, because it can be changed into a prime (12353250414601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2058875069431 + ... + 2058875069436.

It is an arithmetic number, because the mean of its divisors is an integer number (4117750138868).

Almost surely, 212353250416601 is an apocalyptic number.

It is an amenable number.

12353250416601 is a deficient number, since it is larger than the sum of its proper divisors (4117750138871).

12353250416601 is an equidigital number, since it uses as much as digits as its factorization.

12353250416601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4117750138870.

The product of its (nonzero) digits is 129600, while the sum is 39.

The spelling of 12353250416601 in words is "twelve trillion, three hundred fifty-three billion, two hundred fifty million, four hundred sixteen thousand, six hundred one".

Divisors: 1 3 4117750138867 12353250416601