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1235500342401 = 31333739392083
BaseRepresentation
bin10001111110101001100…
…011110001110010000001
311101010001010212100122210
4101332221203301302001
5130220301041424101
62343325300052333
7155155564430403
oct21765143616201
94333033770583
101235500342401
11436a77808846
1217b5466940a9
138c679383580
1443b27278b73
15222116507d6
hex11fa98f1c81

1235500342401 has 16 divisors (see below), whose sum is σ = 1774577919296. Its totient is φ = 760082412096.

The previous prime is 1235500342399. The next prime is 1235500342421. The reversal of 1235500342401 is 1042430055321.

It is not a de Polignac number, because 1235500342401 - 21 = 1235500342399 is a prime.

It is a super-2 number, since 2×12355003424012 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1235500342421) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4564495 + ... + 4827588.

It is an arithmetic number, because the mean of its divisors is an integer number (110911119956).

Almost surely, 21235500342401 is an apocalyptic number.

It is an amenable number.

1235500342401 is a deficient number, since it is larger than the sum of its proper divisors (539077576895).

1235500342401 is a wasteful number, since it uses less digits than its factorization.

1235500342401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9395472.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 1235500342401 its reverse (1042430055321), we get a palindrome (2277930397722).

The spelling of 1235500342401 in words is "one trillion, two hundred thirty-five billion, five hundred million, three hundred forty-two thousand, four hundred one".

Divisors: 1 3 13 39 3373 10119 43849 131547 9392083 28176249 122097079 366291237 31679495959 95038487877 411833447467 1235500342401