Base | Representation |
---|---|
bin | 1011010000010110000101… |
… | …0001000001010000010111 |
3 | 1121211002011011210211120112 |
4 | 2310011201101001100113 |
5 | 3110224341223200234 |
6 | 42153110102153235 |
7 | 2415044520511652 |
oct | 264054121012027 |
9 | 47732134724515 |
10 | 12375432631319 |
11 | 3a4143410351a |
12 | 147a53742281b |
13 | 6b9cc931c884 |
14 | 30ad8d054899 |
15 | 166da7b03ace |
hex | b4161441417 |
12375432631319 has 4 divisors (see below), whose sum is σ = 12389447844696. Its totient is φ = 12361417417944.
The previous prime is 12375432631301. The next prime is 12375432631321. The reversal of 12375432631319 is 91313623457321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12375432631319 - 28 = 12375432631063 is a prime.
It is a super-2 number, since 2×123754326313192 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12375432631339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7007605364 + ... + 7007607129.
It is an arithmetic number, because the mean of its divisors is an integer number (3097361961174).
Almost surely, 212375432631319 is an apocalyptic number.
12375432631319 is a deficient number, since it is larger than the sum of its proper divisors (14015213377).
12375432631319 is an equidigital number, since it uses as much as digits as its factorization.
12375432631319 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14015213376.
The product of its digits is 2449440, while the sum is 50.
The spelling of 12375432631319 in words is "twelve trillion, three hundred seventy-five billion, four hundred thirty-two million, six hundred thirty-one thousand, three hundred nineteen".
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