Base | Representation |
---|---|
bin | 1011010000111101100111… |
… | …1101011001100011100111 |
3 | 1121212002112221111021220202 |
4 | 2310033121331121203213 |
5 | 3110413111122400303 |
6 | 42202023251021115 |
7 | 2415601542225662 |
oct | 264173175314347 |
9 | 47762487437822 |
10 | 12386047465703 |
11 | 3a4599098871a |
12 | 14805ba29a79b |
13 | 6baccb4caa72 |
14 | 30b6b8b026d9 |
15 | 1672c995ec88 |
hex | b43d9f598e7 |
12386047465703 has 4 divisors (see below), whose sum is σ = 13037944700760. Its totient is φ = 11734150230648.
The previous prime is 12386047465699. The next prime is 12386047465723. The reversal of 12386047465703 is 30756474068321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12386047465703 - 22 = 12386047465699 is a prime.
It is a super-2 number, since 2×123860474657032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12386047465723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325948617500 + ... + 325948617537.
It is an arithmetic number, because the mean of its divisors is an integer number (3259486175190).
Almost surely, 212386047465703 is an apocalyptic number.
12386047465703 is a deficient number, since it is larger than the sum of its proper divisors (651897235057).
12386047465703 is an equidigital number, since it uses as much as digits as its factorization.
12386047465703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 651897235056.
The product of its (nonzero) digits is 20321280, while the sum is 56.
The spelling of 12386047465703 in words is "twelve trillion, three hundred eighty-six billion, forty-seven million, four hundred sixty-five thousand, seven hundred three".
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