Base | Representation |
---|---|
bin | 10111000101011110… |
… | …10110000001111111 |
3 | 1011222202111020211021 |
4 | 23202233112001333 |
5 | 200340330341130 |
6 | 5405502205011 |
7 | 616064142223 |
oct | 134257260177 |
9 | 34882436737 |
10 | 12393996415 |
11 | 52900a6a49 |
12 | 249a883767 |
13 | 12269835b8 |
14 | 85809c783 |
15 | 4c814a37a |
hex | 2e2bd607f |
12393996415 has 4 divisors (see below), whose sum is σ = 14872795704. Its totient is φ = 9915197128.
The previous prime is 12393996403. The next prime is 12393996427. The reversal of 12393996415 is 51469939321.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (12393996403) and next prime (12393996427).
It is a cyclic number.
It is not a de Polignac number, because 12393996415 - 219 = 12393472127 is a prime.
It is a super-2 number, since 2×123939964152 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1239399637 + ... + 1239399646.
It is an arithmetic number, because the mean of its divisors is an integer number (3718198926).
Almost surely, 212393996415 is an apocalyptic number.
12393996415 is a deficient number, since it is larger than the sum of its proper divisors (2478799289).
12393996415 is an equidigital number, since it uses as much as digits as its factorization.
12393996415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2478799288.
The product of its digits is 1574640, while the sum is 52.
The spelling of 12393996415 in words is "twelve billion, three hundred ninety-three million, nine hundred ninety-six thousand, four hundred fifteen".
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