12397126143847 has 4 divisors (see below), whose sum is σ = 12506835224880. Its totient is φ = 12287417062816.

The previous prime is 12397126143823. The next prime is 12397126143863. The reversal of 12397126143847 is 74834162179321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12397126143847 is a prime.

It is a Smith number, since the sum of its digits (58) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12397126143791 and 12397126143800.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12397126143947) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54854540347 + ... + 54854540572.

It is an arithmetic number, because the mean of its divisors is an integer number (3126708806220).

Almost surely, 2^{12397126143847} is an apocalyptic number.

12397126143847 is a deficient number, since it is larger than the sum of its proper divisors (109709081033).

12397126143847 is a wasteful number, since it uses less digits than its factorization.

12397126143847 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109709081032.

The product of its digits is 12192768, while the sum is 58.

The spelling of 12397126143847 in words is "twelve trillion, three hundred ninety-seven billion, one hundred twenty-six million, one hundred forty-three thousand, eight hundred forty-seven".