Search a number
-
+
1240022113 = 11112729283
BaseRepresentation
bin100100111101001…
…0011110001100001
310012102022122112221
41021322103301201
510014421201423
6323013551041
742505004551
oct11172236141
93172278487
101240022113
11586a61a70
122a7345481
13169b980c5
14ba98b161
1573ce3e5d
hex49e93c61

1240022113 has 4 divisors (see below), whose sum is σ = 1352751408. Its totient is φ = 1127292820.

The previous prime is 1240022053. The next prime is 1240022129. The reversal of 1240022113 is 3112200421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240022113 - 213 = 1240013921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1240022153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56364631 + ... + 56364652.

It is an arithmetic number, because the mean of its divisors is an integer number (338187852).

Almost surely, 21240022113 is an apocalyptic number.

It is an amenable number.

1240022113 is a deficient number, since it is larger than the sum of its proper divisors (112729295).

1240022113 is a wasteful number, since it uses less digits than its factorization.

1240022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112729294.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1240022113 is about 35213.9477054192. The cubic root of 1240022113 is about 1074.3434571918.

Adding to 1240022113 its reverse (3112200421), we get a palindrome (4352222534).

The spelling of 1240022113 in words is "one billion, two hundred forty million, twenty-two thousand, one hundred thirteen".

Divisors: 1 11 112729283 1240022113