Search a number
-
+
12400552503231 = 34133517501077
BaseRepresentation
bin1011010001110011101010…
…0001101110011110111111
31121220110222211021112201220
42310130322201232132333
53111132312420100411
642212422444204423
72416624152062064
oct264347241563677
947813884245656
1012400552503231
113a51054674042
121483387b39713
136bc4a06368c9
1430c2932c2c6b
151678780a3b06
hexb473a86e7bf

12400552503231 has 4 divisors (see below), whose sum is σ = 16534070004312. Its totient is φ = 8267035002152.

The previous prime is 12400552503223. The next prime is 12400552503277. The reversal of 12400552503231 is 13230525500421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12400552503231 - 23 = 12400552503223 is a prime.

It is a super-2 number, since 2×124005525032312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12400552503192 and 12400552503201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12400552503211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2066758750536 + ... + 2066758750541.

It is an arithmetic number, because the mean of its divisors is an integer number (4133517501078).

Almost surely, 212400552503231 is an apocalyptic number.

12400552503231 is a deficient number, since it is larger than the sum of its proper divisors (4133517501081).

12400552503231 is an equidigital number, since it uses as much as digits as its factorization.

12400552503231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4133517501080.

The product of its (nonzero) digits is 36000, while the sum is 33.

The spelling of 12400552503231 in words is "twelve trillion, four hundred billion, five hundred fifty-two million, five hundred three thousand, two hundred thirty-one".

Divisors: 1 3 4133517501077 12400552503231