1240100115 has 8 divisors (see below), whose sum is σ = 1984160208. Its totient is φ = 661386720.

The previous prime is 1240100111. The next prime is 1240100137. The reversal of 1240100115 is 5110010421.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1240100115 - 2² = 1240100111 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15), and also a Moran number because the ratio is a prime number: 82673341 = 1240100115 / (1 + 2 + 4 + 0 + 1 + 0 + 0 + 1 + 1 + 5).

It is a junction number, because it is equal to n+sod(n) for n = 1240100094 and 1240100103.

It is not an unprimeable number, because it can be changed into a prime (1240100111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41336656 + ... + 41336685.

It is an arithmetic number, because the mean of its divisors is an integer number (248020026).

Almost surely, 2^1240100115 is an apocalyptic number.

1240100115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1240100115 is a deficient number, since it is larger than the sum of its proper divisors (744060093).

1240100115 is an equidigital number, since it uses as much as digits as its factorization.

1240100115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82673349.

The product of its (nonzero) digits is 40, while the sum is 15.

The square root of 1240100115 is about 35215.0552321021. The cubic root of 1240100115 is about 1074.3659834517.

Adding to 1240100115 its reverse (5110010421), we get a palindrome (6350110536).

The spelling of 1240100115 in words is "one billion, two hundred forty million, one hundred thousand, one hundred fifteen".